# Each Edge of a cube is increased by 50%.Find the percentage change in the area of cube.

2
by AryanSinghRajpoot
u mean surface area or volume???
Yes

2016-01-29T20:36:44+05:30
Let the initial side be x
∴its volume is x³.
it is increased by 50%
∴x+x/2    is the final side.
its volume =(3x/2)³
=27x³/8

=(27-8)x³/8
=19x³/8=y/100  of x³
=19/8=y/100
1900/8 =y
∴y=237.5
we have to divide it by 100 because it is in  %
∴% increase in volume was 2.375%

hope it helps and pls mark as best answer
it is clearly mentioned in the Q to find the % change in AREA OF THE CUBE
You considered volume here which makes whole of your ans wrong
2016-01-29T20:40:57+05:30
Let the edge of cube be x
Surface area = 6x²
50% increased edge = x+ (50/100)× 100
= x+  x/2
= (2x+x)/2
= 3x/2
New area = 6(3x/2)²
= 6(9x²/4)
= 27x²/2
Change in areas = 27x²/2  - 6x²
= (27x² - 12x²)/2
= 15x²/2
5 change in areas = [(15x²/2)/6x²]× 100
= [15x²/12x²]× 100
= (15/12) × 100
= 125
% change in areas = 125%
and**
area and surface area are one and the same
:O
ok\
.......h