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2016-01-30T09:48:19+05:30

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Let the sum be P
As , A = P(1 +R/100)^t
⇒A = P(1+10/100)
Interest = P/10
now, for 3rd year interest, the amount at the end of 2nd year will be sum.
i.e.
A = P(1 +10/100)^2
   =121P/100
now amount for 3rd year will be
A = (121P/100)(1 +10/100)
   =1331P/1000
interest = 331P/1000
A/q
P/10 + 331P/1000 = 2652
⇒431P/1000 = 2652
⇒P ≈ Rs 6153
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