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Break down each factor to its prime factors.

You need to keep the max exponent for each prime factor.

The lowest common factor would be ......

We need to find the common factor greater than 99.

Multiplying by 4 would only reach 96.

Multiply by 5.

"which is the smallest 3 digit number which is exactly divisible by 6,8, 12"

120.

You need to keep the max exponent for each prime factor.

The lowest common factor would be ......

We need to find the common factor greater than 99.

Multiplying by 4 would only reach 96.

Multiply by 5.

"which is the smallest 3 digit number which is exactly divisible by 6,8, 12"

120.

### This Is a Certified Answer

Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.

First we have to find ,smallest number,who is divisible by 6,8,12 by using l.c.m

l.c.m of 6,8,12 = 24

there 24*2,24*3,24*4,and 24*5 are also divisible by 6,8,12

but 24*2=48, 24*3=72 ,24*4=96 are two digit numbers ,so smallest no. ,divisible by 6,8,12 =24*5=120

l.c.m of 6,8,12 = 24

there 24*2,24*3,24*4,and 24*5 are also divisible by 6,8,12

but 24*2=48, 24*3=72 ,24*4=96 are two digit numbers ,so smallest no. ,divisible by 6,8,12 =24*5=120