Answers

  • qais
  • Content Quality
2016-01-31T07:34:22+05:30
As the two cones are similar, so the ratio of their dimensions will be same.
i.e.
r/R = h/H =l/L
now, Volume =(1/3)π r² h
v/V =((1/3)π r² h)/((1/3)π R² H)
⇒12π/96π = r²h/R²H = r³/R³ ( as the ratio is same)
⇒r³/R³ =1/8
⇒r/R =1/2
now, curved surface area = πr l
C.S.A1/C.S.A2 = (πr l)/(πR L)
⇒15π/C.S.A2 = r²/R² (as the ratio is same )
⇒15π/C.S.A2 =1/4
∴C.S.A2 =60π square units
Biggest one has the curved surface area = 60π square units 
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hope now you understand my explanation :)
2016-02-01T08:09:50+05:30
Let smaller cone radius be r =12pi cu.
and bigger one be R=96pi cu.
so if rcu./Rcu.= 12pi/96pi=1/8
r/R=12
and rsq./Rsq.=1/4
therefore we can say that in comparison of their ratios with their csa is
15sq./csa2= 1/4
15×4=csa2
60=csa2
hence csa of larger cone is 60pi sq.
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