Answers

2016-01-30T21:28:30+05:30
Metals at the bottom of the activity series are often found in free state. Their reactivity with other atoms is very low. The oxides of these metals can be reduced by heart alone and sometimes by displacement from their aqueous solutions.
1)displacement from aqueous solution :
Example :Ag2S+ 4CN gives rise to 2{Ag(CN)2}^- +S^2-
2{Ag(CN)2}^- +Zn gives rise to {Zn(CN)4}^2- +2Ag
0
2016-01-31T01:20:02+05:30
The metals at the bottom of the activity series are found in free state often. Their reactivity with other atoms also is very low. The oxides of these metals can be reduced only by heart and sometimes by displacement from their aqueous solutions.
1)displacement from aqueous solution :
Example :Ag_{2}S+ 4CN gives rise to 2{Ag(CN)_{2}}^- +S^2-
2{Ag(CN)_{2}}^- +Zn gives rise to {Zn(CN)_{4}}^2- +2Ag

0