I have 4 yellow balls, 3 red balls, 2 blue balls and 1 green ball. I intend to put them into a translucent, colorless acrylic tube, where they will be on top of each other vertically. In how many different ways I can form this column balls so that the yellow and red are together?
a) 2500

b) 500

c) 10!

d) 25200



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There are
4 yellow balls
3 red balls
2 blue ball
1 green
Total number of arrangements 10!/4!3!=25200
2 5 2
which answer is correct
I did so, I was wanting to compare, thank you girl