Answers

2016-02-02T10:49:24+05:30
N (s)=36
(a)8  is n (e)/n (s) = 5/36
(b)13  is n(e)/n(s) = 0/36 =0
(c)less than  or equal to 12  is n(e)/n(s) = 36/36 = 1/1 = 1

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2016-02-02T12:27:29+05:30
Total no.of outcomes = 36
n(S) = 36
(a) Let E be the event of getting sum 8
 No.of favourable outcomes = 4    [ 2,6   6,2  3,5  5,3 ]
n(E) = 4
p(E) = 4/36 = 1/9
(b) Let E be the event of getting a sum 13
n(E) = 0
p(E) = 0/36 = 0
(c) Let E be the event of getting a sum less than 12
n(E) = 36
p(E) = 36/36 = 1
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