# In a km race, A beat B by 50meters and B beat C by 40 meters. find, by how much distance A beats C in a race of .5km.

1
by seemab

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by seemab

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This means that C is 50+40 m=90m behind A when A finishes the race.

The time required for the three participants in the above race is same.let it be t.

now,time=distance/speed

let x,y,z be the speeds of A,B,C respectively.

so by the time formula:

t=(1000/x)=(950/y)=(910/z)----eqn1

in .5km race the speeds of the three participants will be the same.

so dividing the eqn1 by 2 we get:

(t/2)=(500/x)=(475/y)=(455/z)

so in .5km race when A finishes the race C has covered 455m.

so he is behind A by (500-455)m

=45m

so A beats C by 45 m in .5km race