Answers

2016-02-03T03:09:14+05:30

This Is a Certified Answer

×
Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
Total nos. of bulbs=200
total nos. of defective bulbs=12
so,total no. of non defective bulbs=200-12=188 bulbs

hence ,probability of drawing a non defective bulb=(nos. of non-defective bulbs)/(total nos. of bulbs)

=188/200
=0.94
0
thank you so much Faisal07 yes 47/50
most welcome :)
2016-02-03T06:41:26+05:30
P(not defective)=188÷200=0.94
0