# A table cover size 4m*2m is spread ona meeting table.If a uniform width of 25cm of the table covered is hanging all around table.Find the cost of polishing at 2.25 per sq. m

2
Log in to add a comment

Log in to add a comment

Cover length = 4 m = 400 cm

Cover breadth = 2 m = 200 cm

So, table length = 400 - 25 = 375 cm = 3.75 m

table breadth = 200 -25 = 175 cm = 1.75 m

Area of table top = 3.75 X 1.75 sq.m = 6.5625 sq. m

Rate of polishing = Rs 2.25 per 1 sq. m

So, cost = Rs 14.765625

Hope it helped!

=4X2 + 4(4X(0.25))

=12 m^2

total cost=12X2.25=27