# In a house 2 bulbs of 50 w each are used for 5 hours a day and two 70 w each fans are used 10 hours a day . calculate the units of electricity consumed in a month of 30 days

2
by yas9hbu8Csarjithag

2016-02-05T21:18:27+05:30
Power of each bulb=50W=0.05 KW
power of both the bulbs=2*0.05=0.1 KW
units used by the bulbs in a day=0.1*5=0.5 units
power of each fan=70W=0.07KW
power consumed by both fans=0.07*2=0.14
units used by the fans in a day=0.14*10=1.4 units
total units consumed in a day=0.5+1.4=1.9 units
units of energy consumed in a month of 30 days=30*1.9=57 units
ans. therefore 57 units of electricity is consumed in a month in the house
2016-02-05T23:30:24+05:30
Hello!
Energy of bulbs in 30 days = 2×50×5×30 = 15000 Wh = 15000 kJ
Energy of fans in 30 days = 2×70×10×30 = 42000 Wh = 42000 kJ
Total energy consumed by fans and the bubs in 30 day = 15000+42000 = 57000 Wh = 57000 kJ                           Ans.
Or 57 unit of energy .
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