# The heights of two vertical poles are 36m and 28m and the shortest distance btw the tops is 17m. Find how far they are apart.

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From the shorter pole construct a line parallel to ground upto longer pole.

Now, p will be = 8 m

and h given is 17 m

From pythagoras th.

b^2=h^2-p^2

⇒b^2=(17m)^2 - (8m)^2

⇒b^2=289m^2 - 64m^2

⇒b^2=225 m^2

⇒b= root under (225 m^2)

⇒b=15 m

Hence, distance between two poles is 15 m. (Ans)

AB=36m and CD=28m

let E be the point where a line parallel to the ground meets AB

we have to find CE

AC= hypotenuse of the right ΔACE=17m

and AE= 36-28=8m

in ΔACE, By Pythagoras Theorem,

289-64=225

CE=√225=15m

as therefore they are separated by a distance of 225m