# If polynomial ax^3+3x^2-3 and 2x^3 +5x-a leaves same remainder when each is divided by x-4,then find value of 'a'

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and as the remainder is same so both will be equal

so, 64a+48-3=128+20-a

64a+a=148-45

65a=103

a=1.58

or, ax^3+3x-3=2x^3+5x-a

or, now when we put x=1(any constant),then

a+3-3=2+5-a

or, 2a=7

a = 7/2