Answers

2016-02-06T16:33:39+05:30
Perimeter of square 1=12cm
a1= side of square 1 = 12/4=3cm
perimeter of square 2 = 16cm
a2=side of square 2 = 16/4=4cm
The sum of the qareas of these two squares =  a1^{2} + a2^{2}
= 3^{2} + 4^{2}
=9+16=25 cm^{2}
the area of the larger square, is therefore,25 cm^{2}
the side of the larger square=√25=5cm
The perimeter of the larger square=4*5=20cm 
∴The perimeter of the required square is 20cm
1 3 1
2016-02-08T16:59:55+05:30
4s=12
S=3( length of first square)
4s=16
S=4(lenght of 2nd square)
When we both combine these 2 squares, add their side!! 4+3=7
Perimeter 4S
4*7=28
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