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## Answers

Volume of cuboid=l×b×h

Slant Height = √(r2 + h2)Lateral Surface Area = πrs = πr√(r2 + h2)Total Surface Area

= L + B = πrl + πr2 =πr[l+r]frustum of the coneVolume = (1/3)πh (r12 + r22 + (r1 * r2))Slant Height = √((r1 - r2)2 + h2)LSA OF FRUSTUM -π(r1 + r2)lTSA OF FRUSTUM= πR²+πr²+π(r1 + r2)l

cuboid - tsa of cuboid-2[lb+bh+lh]

lsa of cuboid=2h[l+b]

volume=lbh

**Volume:**V = r 2 h

**Lateral Surface Area:**LSA = 2r h

**(area of the "side" that surrounds the top and bottom circles)**

**Total Surface Area:**TSA = 2r h + 2r 2 .=2r[r+h]

**Volume:**

**Surface Area:**SA = 4r 2[SPHERE]

cone:-

**Volume = (1/3)πr2h**

**Slant Height = √(r2 + h2)**

**Lateral Surface Area = πrs = πr√(r2 + h2)**

**Total Surface Area**

**= L + B = πrl + πr2 =πr[l+r]**

**frustum of the cone**

**Volume = (1/3)πh (r12 + r22 + (r1 * r2))**

**Slant Height = √((r1 - r2)2 + h2)**

**LSA OF FRUSTUM -π(r1**

**+ r**

**2)l**

**TSA OF FRUSTUM= πR²+πr²+π(r1 + r2)l**

cuboid -

**tsa of cuboid-2[lb+bh+lh]**

**lsa of cuboid=2h[l+b]**

**volume=lbh**

**cube-**

**tsa of cube-6[side]²**

**lsa of cube=4[side]²**

**volume =[side]³**