# A 12 gram bullet is accelerated from rest to a speed of 700 m/s as it travels 20 cm in a gun barrel. Assuming the acceleration to be constant, how large was the accelerating force?please reply fast

2
by shanmu54321

2014-07-22T21:42:22+05:30

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V² - u² = 2 a s
a = (700² - 0² )/ 2 * 0.20  = 12.25 * 10^5 m/sec
force = ma = 14700 N    as m = 0.012 kg

check now. a calculation mistake only it was. do you understand the formula.
awesome man!!!!!! TNX
2014-07-22T21:45:21+05:30

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Certified answers contain reliable, trustworthy information vouched for by a hand-picked team of experts. Brainly has millions of high quality answers, all of them carefully moderated by our most trusted community members, but certified answers are the finest of the finest.
m = 12 g = 12/1000 kg = 0.012 kg,
u = 0 m/s
v = 700 m/s
S (distance) = 20 cm = 20/100 m = 0.2 m

Formula used:
v² = u² + 2aS
(700)² = (0)² + 2. a. (0.2)
490000 = 0.4 a
a = 490000/0.4
a = 1225000 m/s²

﻿﻿Force= 1225000 * 0.012
= 147000 newton