Answers

2016-02-10T11:43:57+05:30
P[ \sqrt{2} ]=2+k \sqrt{2} -4=k \sqrt{2} -2=0
k \sqrt{2} =2
k= \sqrt{2} /2
hope this helps
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it isn`t      root2/2  instead it is  2/root2
thanks for correcting
you are welcum
2016-02-10T12:47:16+05:30
Given that √2 is the zero of the polynomial
x² + kx - 4 = 0
⇒ (√2)² + k(√2) - 4 = 0
⇒ 2 + k·√2 - 4= 0
⇒ -2 + k·√2 = 0
⇒ k·√2 = 2
⇒ k = 2/√2
∴ k = √2
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