Critical angle of ray 1: sinc1=1μ1=11.35⇒c1=sin-111.35=47.73° Similarly, critical angle of ray 2: sinc2=1μ2=11.45⇒c2=sin-111.45=43.6° Both the rays will fall on the side AC with angle of incidence (i) equal to 45°. Critical angle of ray 1 is greater than that of i. Hence, it will emerge from the prism, as shown in the figure. Critical angle of ray 2 is less than that of i. Hence, it will be internally reflected, as shown in the figure.