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Find the area of a parallelogram whose adjacent sides are lengths 10 cm and 12 cm and one diagonal is of length 8 cm

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by shanmu54321

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Please reply fast

by shanmu54321

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The Brainliest Answer!

AB=12; BC=10, and diagonal AC=8

area of parallelogram=2(area of triangle ABC)

we can find the area of triangle by using herons formula

s=(AB+BC+AC)/2=(12+10+8)/2=15

area=under root{15(15-12)(15-10)(15-8)}

=15√7 cm^2

area of parallelogram=30√7 cm^2