# The sum of the digits of a two digit number is 12. If 54 is subtracted from the number, the digit get reversed. Find the number

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by Bachu

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by Bachu

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The number is 93

9+3=12

93-54=39

hence the number gets reversed when 54 is subtracted from 93.

( I found this by trial and error method )

9+3=12

93-54=39

hence the number gets reversed when 54 is subtracted from 93.

( I found this by trial and error method )

so, number is (x+10y)

after reversing of digit number will be (y+10x)

a/q,

x+y=12 ------------EQN(1)

now,

(x+10y)-54=(y+10x)

or, -9x+9y=54

or, x-y=-6 --------EQN(2)

on adding EQN(1) & (2)

2x=6

or, x=3

put the value of x in (1)

3+y=12

or, y=9

therefore number will be (x+10y)=(3+10*9)=93