Log in to add a comment

## Answers

3-√6x-√6x+2=0

√3*√3-√3x*√2x-√3x*√2x+√2*√2=0

√3x(√3x-√2)-√2(√3x-√2)=0

(√3x-√2)(√3x-√2)=0

x=√2/√3

Therefore the equation has two equal roots; √2/√3

3x^2-√6x-√6x+2=0 √3x(√3x-√2)-√2(√3x-√2)=0 (√3x-√2)(√3x-√2)=0 x=√2/√3 and x=√2/√3