Answers

2014-07-24T15:38:39+05:30
SinA=15/17
so, cosA=√(1-sin^2A)
      cosA=√{(289-225)/289
      cosA=√64/225=8/17
and,  cosB=12/13
  so,  sinB=√{(1)-(12/13)^2}
         sinB={(169-144)/169}
         sinB=5/13
tanA=sinA/cosA=(15/17)÷(8/17)=15/8
tanB=sinB/cosB=(5/13)÷(12/13) = 5/12
tan(A+B)=(tanA+tanB)÷(1-tanA.tanB)
tan(A+B)=(15/8+5/12)÷(1-15*5/8*12)
                = (45+10)/24÷ (96-75)/96
tan(A+B)=220/21
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