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Ab is parallel to Cd and l is the transversal it intersects AB at x And cd at y proof that

angle bisectors of internal angles form a rectangle

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by swaralishete

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angle bisectors of internal angles form a rectangle

by swaralishete

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AB||cd and l is transversal

<axy=<dxy

=1/2

<dyx

<1=<4

<1=1/2

<axy,<4=1/2

<bxy=1/2

<cyx

therefore <2=<3

<cyd=1/2*180=90

{<cyx plus <dyx=90}

<3 plus<4=90

THUS PXQY IS A RECTANGLE

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