# A rhombus sheet whose perimeter is 32 m and whose one diagonal is 10 m long, is painted on both sides at the rate of Rs.5 per sq. m. Find the cost of painting.

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by shanmu54321

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by shanmu54321

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Perimeter = 4 a = 32 => side = 8m

diagonal c = 10m to find other diagonal d. Then area = c d / 2

cost of painting both sides = 2 * (c d / 2) * 5 Rs

In a Rhombus, c² + d² = 4 a² and c² - d² = 4a² cos Ф

so d² = 4 * 8² - 10² = 156 d = 2 √39 m

Cost = 100 √39 Rs.

diagonal c = 10m to find other diagonal d. Then area = c d / 2

cost of painting both sides = 2 * (c d / 2) * 5 Rs

In a Rhombus, c² + d² = 4 a² and c² - d² = 4a² cos Ф

so d² = 4 * 8² - 10² = 156 d = 2 √39 m

Cost = 100 √39 Rs.

Diagonal-10m

Cost per sq.m- Rs.5

One side= 32/4=8

(Half the other diagonal)=Square route of (8^2-5^2)

= Square route of (64-25)

= Square route of 49

=7m

Other diagonal=7*2=14m

Area of Rhombus= (10*14)/2

=70sq.m

Cost to paint = 70*5

=Rs.350