Answers

2016-02-15T23:33:31+05:30
Given

a = 110 {first number to be divided by 2 and 5}

difference d =10

an=990  {last no to be divided by 2 and 5}

an = a + {n - 1}d

990 = 110 + 10n -10

880 + 10 = 10n

890 = 10n 

n = 89

∴ number of natural numbers between 101 and 999 is 89.
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