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ABCD is a parallelogram: AD base. Now draw bisectors from B meeting CD in F and bisector from D meeting AB in E.

We have EAD =EDC = D/2 and ABF = FBC = B/2

remember B+C = 180 degress and also C+D = 180

So proved.

We have EAD =EDC = D/2 and ABF = FBC = B/2

remember B+C = 180 degress and also C+D = 180

*To prove BF & ED parallel**ie., EDC = D/2 = BFC ie., ED & BF make same angle with CD.**angle BFC = 180 - C - B/2 = B - B / 2 = B/2 or D/2 as angles B = D.**= angle EDC*So proved.