Answers

2016-02-16T18:59:06+05:30
ethanoic acid + sodium carbonate  sodium ethanoate carbon dioxide + water.
2CH3CO2H(aq)   +   Na2CO3(s)            2CH3CO2Na(aq)   +  CO2(g)   +   H2O(l)

therefore, co2 gas is released and we can identify is by passing the gas through lime water...which turns milky when co2 is passed thorough it....
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2016-02-16T19:02:20+05:30
The gas evolved is Carbon dioxide. We will identify it by passing it by lime water.. It will turn milky so its carbon dioxide.
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