Answers

2014-07-25T14:15:38+05:30
ΔH =  nHproducts -  mHreactants
-109.3 = (3*413+326+431) - (4*413+x)
-109.3 = (1239+326+431) - (1652+x)
-109.3 = (1996) - (1652+x)
-109.3 = 344 - x
x = 453.3 kj mol^-1
0