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2016-02-18T14:01:53+05:30

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H=77cm
r₁=4.4cm
r₂=4cm

now find l²=h²+(r₁-r₂)²=5929+0.16=5929.16
so, l=70

now all we have to do is to use this:
"πl(r₁+r₂)+πr₁²+πr₂²"
=[3.14*70*(8.4)]+[3.14*19.36]+[3.14*16]
=1848+60.85+50.29
=1959.14

0
2016-02-18T14:10:18+05:30
 We have, R = external radius =4.4/2 cm=2.2 cm
r = internal radius =42cm=2cm
h = length of the pipe = 77 cm 
Total surface area of a pipe
= Inner curved surface area + outer curved surface area + areas of two bases
= 2πrh+2πRh+2π(R2−r2)
= [968+1064.8+2×227(4.84−4)] cm
²
= (2032.8+447×0.84)cm²
=(2032.8+5.28)cm²=2038.08cm²

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