Answers

2016-02-18T17:40:24+05:30
Let the consecutive numbers be x , x+1, x+2
According to the question
x/5  + (x+1)/3  + (x+2)/4 = 40
⇒ [12x+ 20(x+1) + 15(x+2)]/60 = 40
⇒ [12x + 20x + 20 + 15x + 30]/60 = 40
⇒ [47x + 50]/60 = 40
⇒  47x + 50 = 40 × 60
⇒  47x + 50 = 2400
⇒  47x = 2400 - 50
⇒  47x = 2350
⇒  x = 2350/47
∴  x = 50
∴ The numbers are x= 50, x+1 = 51, x+2 = 52
i,e. 50,51,52
 
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