Given a uniform electric field E→=5 ×103 i⏜ N/C, find the flux of this field through a square of 10 cm on a side whose plane is parallel to the y-z plane. What would be the flux through the same square if the plane makes a 30° angle with the x-axis ?

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Answers

2016-02-19T21:33:19+05:30
When the plane is parallel to the y-z plane: Electric flux, ϕ=E.→A⇀Here:E→= 5×103 i^ N/CA⇀= 10 cm2i^=10-2i^ m2∴ ϕ =5×103 i^.10-2i^⇒ ϕ =50 Weber When the plane makes a 30° angle with the x-axis, the area vector makes 60° with the x-axis. ϕ=E.→A→⇒ϕ=EA cosθ⇒ϕ=5×10310-2cos60°⇒ϕ=502⇒ ϕ =25 Weber
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