A parallel beam of light of 500 nm falls on a narrow slit and the resulting diffraction pattern is observed on a screen 1 m away. It is observed that the first minimum is at a distance of 2.5 mm from the centre of the screen. Calculate the width of the slit. (2)

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Answers

2016-02-19T22:26:24+05:30
The distance of the nth minimum from the center of the screen is,Where, D = distance of slit from screen, λ = wavelength of the light, a = width of the slitFor first minimum, n=1Thus,
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