# Speed of two identical cars are u and 4u at a specific instant,the ratio of the respective distance in which the two cars are stopped from that instant by same breaking force-

1
Log in to add a comment

Log in to add a comment

Solution:

By Newtons third law of motion

here the acceleration a is negative since it is retardation, displacement s is the stopping distance d, u is the initial velocity and v is the final velocity.

Since the objects stops after the motion, v=0

That is

⇒

Lets take as the distance traveled by the car with velocity and as the distance traveled by the car with velocity

The retardation for both the cars is -a

⇒

⇒