Answers

2016-02-20T18:37:27+05:30
In Sodium Fluoride the configuration of Sodium is up to 3s1 and in Rubidium Fluoride the configuration of Rubidium is up to 5s1 that means it has the interruption of d-orbital and also has vacant d-orbital. Due to the vacant d-orbital it can accommodate the water molecules rather sodium cannot. Hence NaF has less solubility than RbF in water.    
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