Answers

2016-02-20T17:12:45+05:30
Let the time taken by larger tap to fill the tank be x then,
time taken by smaller tap= x+9
work done by large tap in 1 hr = 1/x
           ''          smaller tap ''      = 1/x+9
therefore, work done by both in 1hr = 1/x+1/(x+9)  = 1/6
                      
(2x+9) / (x^2+9x) = 1/6
6 (2x+9) = x^2 + 9x
x^2+9x-12x-9 = 0
x^-3x-9 =0
now,by applying x = [-b+or- √(b²-4ac)]÷2a, we get
[3+or-√45] / 2 ≈ (3+- 6.71)/2 = -1.855 or 4.855
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