# A man borrowed a sum of money and agrees to pay off by paying Rs3150 at the end of first year and Rs 4410 at the end of second year .if the rate if C.I. is 5%p.a. ,find the sum...

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by Razz14

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by Razz14

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Let sum be Rs. x

r = 5% p.a

n = 1 year

I = Prn/100 = x*5*1/100 = Rs. x/20

Amount = x+(x/20) = Rs. 21x/20

Second Year:

P = (21x/20)-3150 = Rs. (21x-6300)/20

I = (21x-6300)*5/(100*20) = Rs. (21x-6300)/400

Amount = (21x-6300)/20+(21x-6300)/400

= (420x-126000+21x-6300)/400

= Rs. (441x-132300)/400

If he pays Rs. 4410 now, he would clear off his debt.

∴ Amount = Rs. 4410

=> 4410 = (441x-132300)/400

=> 1764000 = 441x-132300

=> 441x = 1896300

=> x =

The Brainliest Answer!

Rate Percent = 5%

Time = 2 years = 1+1

Interest = PRT/100

= x * 5 * 1/100

= x/20

Den he pays 3150 at the end of first year

So principal for second year = x + x/20 - 3150

= 21x/20 - 3150

Interest for second year = (21x/20 - 3150) * 5*1 /100

= (21x/20 - 3150) /20

So amount left after second year = (21x/20 - 3150) + [(21x/20 - 3150) /20]

He clears the amount by paying 4410 at the end of the second year

So,

21x - 3150 * 20 + 21x - 3150 = 4410

-------------------- ---------------

20 400

420x - 3150*20*20 + 21x - 3150 = 4410

-------------------------------------------

400

441x - 1263150 = 4410*400

441x - 1263150 = 1764000

441x = 1764000+1263150

441x= 3027150

x = 6864.28