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One of the exterior angles of a triangle is 80 degrees and the interior opposite angles are in the ratio 3 :5 . find the angles of the triangle

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by ultrab30

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by ultrab30

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Exterior angle = sum of interior opposite angles

let the interior angles be 3x and 5x

80=3x+5x

80=8x

x= 10

the angles are 30,50

the other angle is 180-(30+50) = 100

let the interior angles be 3x and 5x

80=3x+5x

80=8x

x= 10

the angles are 30,50

the other angle is 180-(30+50) = 100

The Brainliest Answer!

Let on interior angle=3x

other interior angle =5x

3x+5x=80

8x=80

x=10 degree

first angle=30 degree

2nd angle = 50 degree

3rd angle=100 degree