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## Answers

So, Volume of 2M HCl required to make 1L of 3M HCl (V2) = (1-x) L

Let us take M1 = 6M and M2 = 2M,

We know that, Molarity of a mixture equation :

(M1V1 + M2V2) / (V1 + V2) = M3

[6x + 2(1-x)] / 1 = 3

6x - 2x + 2 = 3

4x = 1 x = 1/4 = 0.25 L

Therefore, Volume of 6M HCl = 0.25L and Volume of 2 M HCl = 1-0.25 = 0.75 L