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## Answers

To prove :- ABCD is a llgm

Proof :- AB = CD =3 cm (given )

angle CDB = angle ABD = 90 degree (Given )

If angle CDB = angle ABD , then AB ll CD ( Angle CDB & angle ABD are alternate intr. angles and they are equal )

Therefore QUAD ABCD is a llgm (A quad with a pair of opposite sides equal and parallel is a parallelogram. )

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