# Calculate the work required to stop the car of 1500kg moving at a speed of 72km/h by applying brakes.

2
by riya34

2016-02-25T10:34:30+05:30

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Work done = change in kinetic energy
final velocity = 0 m /s
initial velocity = 72×5/18 = 20 m/s

1/2 ×1500 (0×0-20×20)
750×-400
=-300000 J

mark as best plzz
• Brainly User
2016-02-25T13:33:34+05:30

### This Is a Certified Answer

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⇒Work done=Change in kinetic energy............ ⇒KE=1/2mv²....... ⇒Mass->15000kg........ ⇒Velocity->72km/h...... ⇒KE=1/2×15000×(72)²....... ⇒KE=1/2×15000×5184....... ⇒KE=7500×5184...... ⇒KE=3888×10×10³J........ So work require will be 3888×10×10³J.......!!