Answers

2016-02-25T16:10:44+05:30
ΔACB  is  similar toΔPBQ
PQ\AB=QR\BC=PR|AC
PQ=8 cm andAb=6 cm
AB/PQ=6/8=3/4
steps
draw  triangle ABC with  base side AB with given measurements
Draw  angle BAX
cut 4  equal parts  say a1 a2 a3 and a4 on AX
join a4B and  draw a3B parallel to  a4B
Draw B-C- parallel  toBC which cuts AC at C-.ΔC-AB is a required triangle


0
is this ans ok
please mark as brainest ans