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## Answers

**Solution....**

1 mole of Na2CO3 gives 1 mole of CO2

1 mole of Na2CO3 gives 1 mole of CO2

105.98g of Na2CO3 = 44g of CO2

therefore,

9.85g of Na2CO3 = (44*9.85)/105.98 g of CO2

=4.0894 g

**Number of moles of CO2 = mass / molar mass**

= 44/4.0894 = 0.0929 moles

**1 mole of CO2 = 22.4 l**

0.0929 moles = 22.4*0.0929 = 2.0809 l

**Volume of CO2 = 2.0809 l**

Equation is given in the pic below...

Equation is given in the pic below...