#
ABCD is a trapezium in which its diagonals intersect at O. Show that the area of triangle AOD is equal the area of triangle BOC.

1
by laura

thank-you

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by laura

thank-you

No problem!

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The Brainliest Answer!

Ar(ΔACD) = Ar(ΔBDC)

(Theorem: Triangles with same base that fall between the same two parallel lines have equal areas)

=> Ar(ΔAOD)+Ar(ΔDOC) = Ar(BOC)+Ar(DOC) (sum of component triangles)

=>

Thus proved.