Step 1: A line segment AB= 11 cm is drawn. (XY + YZ + ZX = 11 cm)
Step 2: An angle, ∠A= 30° is constructed at point A and an angle ∠B = 90° at point B.
Step 3: ∠A and ∠B are bisected . The bisectors of these angles intersect each other at point X.
Step 4: Perpendicular bisectors TS of AX and ZU of BX are constructed.
Step V: Let TS intersect ABat Y and ZU intersect AB at Z. XY and XZ are joined.
Thus, ΔXYZ is the required triangle.