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## Answers

**D**raw a line segment

**AB**of 11 cm

**C**onstruct 30° from

**A**and 90° from

**B**

**C**onstruct angle bisectors for both the angles

**T**hey will meet at

**X**

**C**onstruct perpendicular line bisector for

**AX**and

**BX**.

**T**he both lines will meet

**AB**at X and

**Y**

**J**oin

**XY**and

**XZ**

**XYZ**is our required triangle.

Step 1: A line segment AB= 11 cm is drawn. (XY + YZ + ZX = 11 cm)

Step 2: An angle, ∠A= 30° is constructed at point A and an angle ∠B = 90° at point B.

Step 3: ∠A and ∠B are bisected . The bisectors of these angles intersect each other at point X.

Step 4: Perpendicular bisectors TS of AX and ZU of BX are constructed.

Step V: Let TS intersect ABat Y and ZU intersect AB at Z. XY and XZ are joined.

Thus,

**ΔXYZ**is the required triangle.