## Answers

internal diameter = 2 cm

radius = 2/2 cm = 1cm

water flows at the rate of 0.7 m/s.

In 1 second it covers distance = 0.7 m = 70 cm

volume of water flows in 1 second = πr²d = 3.14 x 12 x 70 = 219.8 m³

Thus volume of water flows in 1 and half hour = 5400 x 219.8 = 1186920 m³

radius of cylindrical tank (r) = 40 cm

Let the increase level of water = h cm

Volume of cylindrical tank = π(40)²h

Si water flows out at the rate of 0.7 m/s into a cylindrical tank.

So,volume of water flows in 1and half hour = Volume of cylindrical tank

1186920 m³= π(40)²h

h = 1186920 / ((3.14 x (40)²)

h = 236.25 m

Hence, water rise by 236.25 m.

vol.of cylindrical tank=1600h

so h=126000/1600

=78.75cm