# A right circular cone is 4.1 cm high and the radius of its base is 2.1 cm another right circular cone is 4.3 cm high and the radius of the base is 2.1 cm both the cones are melted together and recast into a sphere. find the diameter of the sphere.

2
by A3MUTfatm6akhi

2016-02-27T13:53:21+05:30

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First cone
A = πr (r+√(h²+r²))
A = π*2.1 (2.1+√(h²+2.1²))
A = 3.14*2.1 (2.1+√(4.1²+2.1²))
A = 44.25cm²

Second cone
A = πr (r+√(h²+r²))
A = π*2.1 (2.1+√(h²+2.1²))
A = 3.14*2.1 (2.1+√(4.3²+2.1²))
A = 45.43cm²

Area of sphere = 4πr²
45.43 + 44.25 = 4 * 3.14 * r²
89.68 = 12.56 * r²
7.14 = r²
r = 2.67cm
Therefore, Diameter = 2 * 2.67 = 5.34cm
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It is sphere buddy...! Not hemisphere so please correct it ;)
Mark as brainliest plzzzzz ;)
2016-02-27T13:55:58+05:30
V o l u m e  o f  t h e  f i r s t  c o n e = π × 2 . 1 2 × 4 . 1 3 V o l u m e  o f  t h e    s e c o n d  c o n e  = π  × 2 . 12 × 4 . 33 t o t a l  m a t e r i a l  =  π × 2 . 1 2 3 ( 4 . 1 + 4 . 3 ) = 12 . 348 π  c m  3  i f  t h e  r a d i u s o f  t h e s p h e r e = r t h e n  4 π r 3 3 = 12 . 348 π r = 2 . 08 c m  d i a m e t e r  o f  t h e  s p h e r e = 4 . 16 cm