# Water is flowing at 7m/s through a circular pipe of internal diameter of 2cm into cylindrical tank,the radius of whose base is 40cm. Find the increase in water level in 30 minutes.

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by rk57117

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by rk57117

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o length of pipe in which the water has traveled,

h = 7(1800) = 12600m

Radius of the pipe(r)= 1cm

Radius of the cylinder(R)= 40 cm

let the height of the water in the tank H

So,

Volume of water coming from the pipe = Volume of water in the cylindrical tank.

πr^2h = πR^2h

H = {(0.01)^2 X 12600}/(0.4)^2 = 7.875m (ans)

rate of flow =7m s- for pipe:

radius = 1cm or 0.01m for tank :

radius = 40cm or 0.4m time = 1/2hr = 30min =1800sec according to formula area of cross section = area of pipe *speed * time

pi r2h = pi R2 * 7*4800

h = 0.01*0.01*7*1800/0.4*0.4

h= 7.875