# What is the pH of 0.05 of Ba(OH)2

2
by talique

2016-02-27T16:32:47+05:30

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Its 13 if u want explanation plzz see below
Ba(OH)2 ↔ Ba2+ + 2OH-
0.05M Ba(OH)2 = 0.05*2 = 0.1MOH-
[OH-] = 0.1
pOH= -log 0.1
pOH = 1.00
pH = 14.00-pOH
pH = 13.00
mark as best plz
wher 14 comes from
2016-02-27T16:42:00+05:30

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Its ph will be 13.

as:  Ba(OH)2 - Ba2+  + 2OH- 0.05 M X 2= 0.10M   pOH= -log(0.10 M) = 1.00

pH = 14-pOH

= 14 - 1.00=13

plz mrk dis brainliest
wher 14 comes from