# A circular park whose circumference is 352 meters is surrounded by a road.If the area of the road is 2618 sq m , calculate the width of the road .

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by Kayra1

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by Kayra1

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The Brainliest Answer!

circumference of a circular park = 352m

area of the road = 2618 m²

proof,

circumference of a circle = 2×22/7×r

352 = 2×22/7×r

(352×7) / (22×2) = r

56 m = r

area of the circle =22/7×r²

area of the circular park = 22/7×56×56

= 22×8×56

= 9856 m²

area of the of the circular road = 2618 m²

radius of the park + width of the road = bigger radius

let us take the bigger radius = a

than,

a = 56+ width of the road

area of the bigger circle(road+park) = area of the park+area of the road

area of the bigger circle(road+park) = 9856+2618

= 12474 m²

area of the bigger circle(road+park) = 22/7×r²

12474 =22/7×r²

(12474 × 7) / 22 = r²

3969 = r²

63 = r (radius of the bigger circle)

radius of the bigger circle - radius of the park = width of the road

63 - 56 = 7

therefore, the width of the road = 7 m